Submission #1864395


Source Code Expand

#include"bits/stdc++.h"


#define PB push_back
#define PF push_front
#define LB lower_bound
#define UB upper_bound
#define fr(x) freopen(x,"r",stdin)
#define fw(x) freopen(x,"w",stdout)
#define iout(x) printf("%d\n",x)
#define lout(x) printf("%lld\n",x)
#define REP(x,l,u) for(int x = (l);x<=(u);x++)
#define RREP(x,l,u) for(int x = (l);x>=(u);x--)
#define mst(x,a) memset(x,a,sizeof(x))
#define PII pair<int,int>
#define PLL pair<ll,ll>
#define MP make_pair
#define se second
#define fi first
#define dbg(x) cout<<#x<<" = "<<(x)<<endl;
#define sz(x) ((int)x.size())
#define cl(x) x.clear()

typedef  long long ll;
typedef unsigned long long ull;
typedef double db;
typedef long double ld;
using namespace std;

const int maxn = 100010;
const int mod = 1e9+7;
const int MAX = 1000000010;
const double eps = 1e-6;
const double PI = acos(-1);

template<typename T> inline void read(T &x){
x=0;T f=1;char ch;do{ch=getchar();if(ch=='-')f=-1;}while(ch<'0'||ch>'9');do x=x*10+ch-'0',ch=getchar();while(ch<='9'&&ch>='0');x*=f;
}

template<typename A,typename B> inline void read(A&x,B&y){read(x);read(y);}
template<typename A,typename B,typename C> inline void read(A&x,B&y,C&z){read(x);read(y);read(z);}
template<typename A,typename B,typename C,typename D> inline void read(A&x,B&y,C&z,D&w){read(x);read(y);read(z);read(w);}
template<typename A,typename B> inline A fexp(A x,B p){A ans=1;for(;p;p>>=1,x=1LL*x*x%mod)if(p&1)ans=1LL*ans*x%mod;return ans;}
template<typename A,typename B> inline A fexp(A x,B p,A mo){A ans=1;for(;p;p>>=1,x=1LL*x*x%mo)if(p&1)ans=1LL*ans*x%mo;return ans;}

int n,m,Q;

ll tim[maxn],A[maxn],Ans[maxn];

void Work(){
	tim[n]=1;
	RREP(i,n,1){
		int k=A[i];
		int t;
		while(t=upper_bound(A+1,A+i,k)-A-1){
			tim[t]+=tim[i]*(k/A[t]);
			k%=A[t];
		}
		Ans[k]+=tim[i];
	}
	RREP(i,m,1)Ans[i]+=Ans[i+1];
	REP(i,1,m)printf("%lld\n",Ans[i]);
}

void Init(){
	read(m,Q);
	A[++n]=m;
	REP(i,1,Q){
		ll x;read(x);
		while(n&&A[n]>=x)n--;
		A[++n]=x;
	}
}

int main(){
	Init();
	Work();
	return 0;
}

Submission Info

Submission Time
Task E - Sequential operations on Sequence
User yanQval
Language C++14 (GCC 5.4.1)
Score 0
Code Size 2088 Byte
Status RE
Exec Time 112 ms
Memory 1280 KB

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 0 / 1400
Status
AC × 2
AC × 10
WA × 1
RE × 27
Set Name Test Cases
Sample s1.txt, s2.txt
All 01.txt, 02.txt, 03.txt, 04.txt, 05.txt, 06.txt, 07.txt, 08.txt, 09.txt, 10.txt, 11.txt, 12.txt, 13.txt, 14.txt, 15.txt, 16.txt, 17.txt, 18.txt, 19.txt, 20.txt, 21.txt, 22.txt, 23.txt, 24.txt, 25.txt, 26.txt, 27.txt, 28.txt, 29.txt, 30.txt, 31.txt, 32.txt, 33.txt, 34.txt, 35.txt, 36.txt, s1.txt, s2.txt
Case Name Status Exec Time Memory
01.txt RE 111 ms 256 KB
02.txt RE 111 ms 256 KB
03.txt RE 111 ms 256 KB
04.txt RE 112 ms 256 KB
05.txt RE 111 ms 256 KB
06.txt RE 111 ms 1024 KB
07.txt RE 111 ms 1024 KB
08.txt RE 110 ms 1024 KB
09.txt RE 112 ms 1024 KB
10.txt RE 110 ms 1024 KB
11.txt RE 111 ms 1024 KB
12.txt RE 110 ms 1024 KB
13.txt RE 110 ms 1024 KB
14.txt RE 110 ms 1024 KB
15.txt RE 111 ms 1024 KB
16.txt RE 110 ms 1024 KB
17.txt RE 110 ms 1024 KB
18.txt RE 110 ms 1024 KB
19.txt RE 111 ms 1024 KB
20.txt RE 112 ms 1024 KB
21.txt RE 108 ms 1024 KB
22.txt RE 109 ms 1024 KB
23.txt RE 111 ms 1024 KB
24.txt RE 108 ms 1024 KB
25.txt RE 109 ms 1024 KB
26.txt RE 108 ms 1024 KB
27.txt AC 14 ms 1280 KB
28.txt AC 14 ms 1280 KB
29.txt AC 14 ms 1280 KB
30.txt AC 15 ms 1280 KB
31.txt AC 1 ms 256 KB
32.txt AC 10 ms 1280 KB
33.txt AC 1 ms 256 KB
34.txt RE 97 ms 256 KB
35.txt AC 1 ms 256 KB
36.txt WA 1 ms 256 KB
s1.txt AC 1 ms 256 KB
s2.txt AC 1 ms 256 KB